Physics, 16.08.2020 01:01 alyssanewsome

Solve for A if F=MA and F=100 and M=25?

Answers: 2

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Answers

Answer from: bekahmc1p6k6vj

$\boxed{ \boxed{ \bold{A = 4}}}$

Explanation:

Given,

F = 100 , M = 25

Now, let's find the value of A

$\sf{F = MA}$

plug the values

⇒ $\sf{100 = 25 A}$

Swap the sides of the equation

⇒ $\sf{25A = 100}$

Divide both sides of the equation by 25

⇒ $\sf{ \frac{25A}{25} = \frac{100}{25} }$

Calculate

⇒ $\sf{A = 4}$

Hope I helped!

Best regards!!

Answer from: mateoperez496

Given:-

Force,F = 100 NMass,m = 25 kg

To find out:-

Calculate the acceleration, a ?

Formula applied:-

F = m × a

Solution:-

We know,

$\sf{F = m × a}$

Substituting the values of mass and acceleration,we get

$\sf\implies \: 100 = 25 \times a$

$\sf \implies a = \cancel \dfrac{100}{25}$

$\sf \implies a = 4 \: ms {}^{ - 1}$

Answer from: Quest

force is based upon mass and acceleration.the statement is not always true.

it can be explained from newton's second law of motion.

as per newton's second law of motion the rate of change of momentum is directly proportional to the applied force and takes place along the direction of force.

mathematically it can be written as -

$f\alpha \frac{dp}{dt}$

⇒ $f= k \frac{dp}{dt}$

here k is the proportionality constant whose value is 1.

$f=\frac{dp}{dt}$

$f= \frac{d[mv]}{dt}$

$f= m\frac{dv}{dt} +v\frac{dm}{dt}$

$f=ma+v\frac{dm}{dt}$ [a is the acceleration=dv/dt]

hence we see that force not only depends on mass and acceleration but also on velocity and rate of change of mass. force f will depend on mass and acceleration only when mass is constant.

hence the statement that force is based upon mass and acceleration is false.

Answer from: Quest

The boat's velocity relative to the riverbank can be resolved into two components. the component going north is 2.7 m/s and the component going west is 1.2 m/s.we add these two vectors and then find the magnitude of the resultant to get the speed.the magnitude of the resultant vector from adding can be obtained by the pythagorean theorem. $\begin{aligned} | \vec{v}| & = \sqrt{(\text{2.7 m/s})^2 + (\text{1.2 m/s})^2 } \\ & = 2.954 \text{ m/s} \end{aligned}$ to two significant figures, the boat's speed relative to the riverbank is 3.0 m/s.

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