What is the force per meter of length on a straight wire carrying a 6.40 A current when perpendicular to a 0.9 T uniform magnetic field

5.76 N/m

Explanation:

From the question,

F = BILsinФ Equation 1

and then,

F/L = BIsinФ Equation 2

Where F/L = force per meter, I = current, B = magnetic field, Ф = angle.

Given: B = 0.9 T, I = 6.4 A, and Ф = 90° (Perpendicular)

Subtitute these values into equation 2

F/L = 0.9(6.4)(sin90°)

F/L = 5.76 N/m

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