A train it speed steading from 10 m/s to 20m/s in 1 minutes average speed during this time in m/s how far does it travel while increase its speed

Explanation:

Given:

v₀ = 10 m/s

v = 20 m/s

t = 60 s

Find: v_avg and Δx

v_avg = ½ (v + v₀)

v_avg = ½ (20 m/s + 10 m/s)

v_avg = 15 m/s

Δx = v_avg t

Δx = (15 m/s) (60 s)

Δx = 900 m

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day