A load of 400 N is lifted by a first class lever in which the load is at the distance of 20 cm and the effort is at the distance of 60 cm from fulcrum If150 N effort is required to lift the load what is its efficiency

2.5 m

Explanation:

Load ( L ) = 500 N

Effort ( E ) = 200 N

Load distance ( LD ) = 3 m

Effort distance ( ED ) = ?

Now, Let's find the Effort distance ( ED )

We know that,

Output work = Input work

i.e L × LD = E × ED

plug the values

multiply the numbers

Swipe the sides of the equation

Divide both sides of the equation by 200

Calculate

Hope this helps..

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