A jet makes a landing traveling due east with a speed of 115 m/s. If the jet comes to rest in 13.0 s, what is the magnitude of its average acceleration

8.846 m/s²

Explanation:

From the question,

The magnitude of the average acceleration is given as,

a = (v-u)/t Equation 1

Where a = acceleration of the jet, v = final velocity of the jet, u = initial velocity of the jet, t = time taken for the jet to come to rest.

Given: v = 115 m/s, u = 0 m/s( from rest), t = 13.0 s

Substitute these values into equation 1

a = (115-0)/13.0

a = 115/13

a = 8.846 m/s²

Hence the magnitude of the average acceleration of the jet is 8.846 m/s²

the answer is 46 mls because when you add the speed per second it increses the speed

this is an example of "committed" time.

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