Suppose the tourist in question 1 instead threw the rockwith an initial velocity of 8.0m/s[down]determine the velocity and the displacement of the rock at4.0s[remember thev is down and must become a 8.0 m/s]

Given:

By using the relation, we get

→

By substituting the values, we get

hence,

→

Thus the above answer is appropriate.    

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The velocity of the rock is 47.24 m/s

The displacement of the rock is 110.48 m

Explanation:

The initial velocity u = 8.0 m/s

time t = 4.0 s

Using

where v is the final velocity of the rock after 4.0 s

u is the initial speed = 8 m/s

g is acceleration due to gravity = 9.81 m/s

t is the time = 4.0 s

substituting, we have

= 47.24 m/s

Also, using

where

s is the distance that the stone fell

t is the time = 4.0 s

g is the acceleration due to gravity = 9.81 m/s^2

substituting values, we have

s = 32 + 78.48

s = 110.48 m

b) returns freshwater to the earth.

c) returns freshwater to the earth.c) occurs after condensation.

d) returns freshwater to the earth.c) occurs after condensation.d) roughly equal to the amount of evaporation.

happy to

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i think it's 35 meters