An electron moving parallel to the x axis has an initial speed of 4.10 106 m/s at the origin. Its speed is reduced to 1.76 105 m/s at the point x = 2.00 cm. Required:
a. Calculate the electric potential difference between the origin and that point.
b. Which point is at the higher potential?

a

b

At the origin

Explanation:

From the question we are told that

   The  initial speed is  

    The  speed at (x = 2.00 cm) is  

Generally the electric potential difference is mathematically represented as

Here W is the  work-done which is mathematically represented as

Here   is the kinetic energy at  x =  2.00 cm mathematically expressed as

and  

        is the kinetic energy at origin  mathematically expressed as

So

Here m is the mass of electron with value

         q  is the charge on the electron with value  

So

So given that the difference is negative then potential is higher at the origin

answer; the correct answer is technician a; ///100%good luck

electrical power