A hiker caught in a rainstorm absorbs 1.00 L of water in her clothing. If it is windy so that the water evaporates quickly at 20 ∘C, how much heat is required for this process?

2260000 J

Explanation:

From the question,

Q = ml Equation 1.

Where Q = Heat, m = mass of water, l = specific latent heat of vaporization.

But we can get the mass o water using the formula of density.

D = m/v Equation 2

Where D = density of water, v = volume of water.

make m the subject of the formula in equation 2

m = D×v Equation 3

Substitute equation 3 into equation 1

Q = D×v×l Equation 4

Given: v = 1.00 L = 0.001 m³.

Constant: l = 226000 J/kg, D = 1000 kg/m³

Substitute these values into equation 4

Q = 0.001(2260000)(1000)

Q = 2260000 J

at positions a, g kinetic energy is maximum.

at position d, potential energy is maximum.