A clock battery wears out after moving 10,900 C of charge through the clock at a rate of 0.450 mA. (a) How long (in s) did the clock run

2.42×10⁷ s

Explanation:

From the question above,

Applying,

Q = It Equation 1

Where Q = quantity of charge in coulombs, I = electric current in Ampere, t = time in seconds

make t the subject of the equation

t = Q/I Equation 2

Given: Q = 10900 C, I = 0.450 mA = 4.5×10⁻⁴ A

Substitute these values into equation 2

t = 10900/(4.5×10⁻⁴)

t = 2.42×10⁷ s

Hence the clock runs for 2.42×10⁷ s