Physics, 31.08.2020 01:01 bapefer498

Find the angles of the first three principal maxima above the central fringe when this grating is illuminated with 672 nm light.

Answers: 3

Show answers

Answers

Answer from: gunner20115

Complete Question

A grating has 767 lines per centimetre.Find the angles of the first three principal maxima above the central fringe when this grating is illuminated with 672 nm light.

The first is

$\theta_1 = 2.92^o$

The second is

$\theta _2 = 5.93^o$

The third is

$\theta _3 = 8.92^o$

Explanation:

From the question we are told that

The number of lines per cm is $I = 767 \ lines/cm = 76700 \ lines / m$

The wavelength is $\lambda = 672nm = 672 *10^{-9} \ m$

Generally the condition for constructive interference is

$dsin (\theta ) = n\lambda$

Here d is the distance of separation of the slit which is mathematically represented as

$d = \frac{1}{l}$

$d = \frac{1}{76700}$

$d = 1.30*10^{-5} \ m$

$\theta_1 = sin^{-1} [\frac{ n \lambda }{ d} ]$

For the first angle n = 1

$\theta_1 = sin^{-1} [\frac{ 1 * 672 *10^{-9} }{ 1.30 *10^{-5}} ]$

$\theta_1 = 2.92^o$

For the second angle n = 2

$\theta_2 = sin^{-1} [\frac{ 2 * 672 *10^{-9} }{ 1.30 *10^{-5}} ]$

$\theta _2 = 5.93^o$

For the second angle n = 3

$\theta_3 = sin^{-1} [\frac{ 3 * 672 *10^{-9} }{ 1.30 *10^{-5}} ]$

$\theta _3 = 8.92^o$

Answer from: Quest

Since you have not included the experiment situation and the data, of course, i can not give you specific details about it. but i can you with this question.1) i will assume that the motion is projectile (parabolic) motion.2) yes, the horizontal distance depends on the horizontal velocity as, naming vx the horizontal velocity and t the time, it is: x = vx × t3) now, observe that the flight time depends on the vertical velocity as, naming voy the initial vertical velocity, t the time and y the vertical distance before reaching the ground: y = yo + voy×t - gt² / 2.the higher the initial vertical velocity (voy) the longer the object will be flying and so t will be higher in the equation for the horizontal distance.that explains the relationship between the horizontal distance and the horizontal velocity.

Answer from: Quest

Ray 2 should cross through the focal point on the right side of the lens

Another question on Physics

Physics, 21.06.2019 19:00

Adelivery truck leaves a warehouse and travels 2.60 km north. the truck makes a left turn and travels 1.25 km west before making another right turn to travel 1.40 km north to arrive at its destination. what is the magnitude and direction of the truck's displacement from the warehouse?

Answers: 2

Answer

Physics, 22.06.2019 14:00

Ascientific blank must be testable and capable of being proven false?

Answers: 1

Answer

Physics, 22.06.2019 19:30

Coal contains energy. a. light b. kinetic c. chemical d. mechanical

Answers: 1

Answer

Physics, 23.06.2019 00:30

Diego kicks a soccer ball from the end line. his fellow students time and mark the soccer ball as it moves down the field. the graph represents the ball's progress. based on the graph, during what time is the velocity constant and positive?

Answers: 1

Answer

You know the right answer?

Find the angles of the first three principal maxima above the central fringe when this grating is il...

Questions