a planet of mass 2*10^24 kg is at location <2*10^11,-4*10^11,0>m. A star of mass 5*10^30 kg is at location <-5*10^11,6*10^11,0>m. The planet is in a circular orbit around the star, moving at a constant speed. What is the gravitational force vector on the planet due to the star

(-2.57*10^20, 3.67*10^20, 0)

Explanation:

Refer to the attachment.

I hope that helps

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day

d) physical means can be used to separate the components of air.