QUESTION 5 A small beaker has 50 mL of water in it. A small frog with a mass of 20 grams is dropped into the beaker. The water level rises to 79
mL. What is the density of the frog? (You know the mass of the frog, first find the volume of the frog, then use the density formula to.

0.69 g/cm^3

Explanation:

Given that a small beaker has 50 mL of water in it. A small frog with a mass of 20 grams is dropped into the beaker. The water level rises to 79mL.

The volume of the frog will be:

79 - 50 = 29mL

Convert it to litre by dividing it by 1000

29/1000 = 0.029 L

Since 1L = 1000 cm^3

Convert it to cm^3 by multiplying it by 1000

0.029 × 1000 = 29 cm^3

Density = mass/volume

Substitute the mass and volume into the formula

Density = 20/29

Density = 0.6896 g/cm3

Therefore, the density of the frog is 0.69 g/cm^3 approximately

3. dark matter

empty space could also be a simple vacuum