a battery of 6v is connected in series with resistors of 0.1 ohm, 0.15 ohm, 0.2 ohm, 0.25 ohm and 6 ohm. how much current would flow through 0.2 ohm resistors

0.9 Amps

Explanation:

Ohm's law: Voltage = Current x Resistance

Rearrange equation:

Current =Voltage/Resistance

Voltage=6v

In a series circuit the total resistance is the sum of all the resistors so the total resistance = 0.1+0.15+0.2+0.25+6=6.7 Ohms

6/6.7 = 0.9 (1dp) Amps

Because it is a series circuit, the current is the same throughout the entire circuit, all the resistors have a current of 0.9 Amps.

Hope this helped!

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