Calculate the speed for each segment on the graph include the units (m/s). Show your calculations, (such as 4/2= 2 m/s) a. (t=0-10s)
b. (t=10-15s)
c. (t=15-30s)
d. (t=30-40s)
e. (t=40-55s)

 v_A = 6 m/s , v_B = 0 m/s ,  v_C = - 4 m/s , v_D = -4 m/s ,     v_E = 2.66 m / s

Explanation:

For this exercise we use the definition of average velocity in each segment

         v_average = (x₂-x₁) / Δt

segment A of the graph you take the value of distance and time

x₁ = 0 m     t₁ = 0 s

x₂ = 60 m   t₂ = 10 s

using the average velocity equation and calculate

         v_A = (60-0) / (10-0)

         v_A = 6 m / s

Segment B

x₁ = 60m

x₂ = 60 m

since the displacement variation is zero (particle stopped) the velocity is zero

         v_B = 0 m / s

Segment C and D

x₁ = 60 m    t1 = 15 s

x₂ = -40 m  t2 = 40 s

        v_C = (-40 -60) / (40 -15)

        v_C = - 4 m / s

Segment D

how is the same line

         v_D = -4 m / s

Segment E

x₁ = -40 m  t₁ = 40 s

x₂ = 0 m    t₂ = 55 s

         v_E = (0- (-40)) / (55 -40)

         v_E = 2.66 m / s

battery with hi vtge high val resist in series

wavelength divides in half and speed stays the same.