The speed needed to escape the pull of Earth's gravity is 11.3 km/s. What is this speed in mi/h? (1 mile = 1609 m)

The value of the speed needed to escape the pull of Earth's gravity in miles per hour (mi/h) is 25282.8.

Given the following data;

In this exercise, you're required to convert the value of the speed needed to escape the pull of Earth's gravity in kilometer per seconds (km/s) to miles per hour (mi/h).

Conversion:

1 mile = 1.609 kilometer

X mile = 11.3 kilometer

Cross-multiplying, we have;

× X =

X = 7.0230 miles

Since we know that one (1) hour is equal to 3600 seconds, we would multiply the value of X by 3600 in order to convert it to miles per hour (mi/h).

X = 7.0230 × 3600

X = 25282.8 mi/h

Therefore, the value of the speed needed to escape the pull of Earth's gravity in miles per hour (mi/h) is 25282.8.

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11.3 km/sec * 1000 m/km / 1609 m/mi = 7.02 mi / sec

7.02 mi/sec * 3600 sec / hr = 25,300 mph

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the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s