An object increases its speed from rest to 35 m/s while traveling over a distance of 400 meters. Determine the acceleration of the object.

1.53 m/s²

Explanation:

Given:

Δx = 400 m

v₀ = 0 m/s

v = 35 m/s

Find: a

v² = v₀² + 2aΔx

(35 m/s)² = (0 m/s)² + 2a (400 m)

a = 1.53 m/s²

that tool is called an altimeter which measures your altitude which can be used to tell which atmosphere you are currently in, including the stratosphere.

hope this ! : )

force required to detach it is given by

charges are taken to be fundamental charge

now we have

so above is the minimum distance at which it will detach