If Justin races his Chevy S-10 down highway 37 north for 2,560 meters in 60 seconds, what is his velocity? a. Draw Justin's trip. What are his distance and displacement? b. The Chevy S-10
started rounding at 10 meters per hour. What is the acceleration at 30 seconds on the
highway? c. The S-10 has a force of 30 N. What is the mass of the car?

A.) 42.7 m/s

B.) 0.33 m/s^2

C.) 90 kg

Explanation:

A.) If Justin races his Chevy S-10 down highway 37 north for 2,560 meters in 60 seconds, what is his velocity? 

Velocity = displacement/time

Velocity = 2560/60

Velocity = 42.67 m/s

B.) The Chevy S-10 started rounding at 10 meters per hour. What is the acceleration at 30 seconds on the highway?

Acceleration = velocity/time

Acceleration = 10/30

Acceleration = 0.33 m/s^2

C.) The S-10 has a force of 30 N. What is the mass of the car?

Force = mass × acceleration

30 = mass × 0.33

Mass = 30/ 0.33

Mass = 90 kg

increase masses, decrease separation