A train travels at a speed of 30 m/s. The train starts at an initial position of 1000 meters and travels for 30 seconds. What is its final position? Answer please

1900 metres

Explanation:

Given that a train travels at a speed of 30 m/s. The train starts at an initial position of 1000 meters and travels for 30 seconds.

The parameters to be considered are:

Speed = 30 m/s

Time = 30 seconds

Speed = distance/time

Substitute the parameters into the formula

30 = distance / 30

Cross multiply

Distance = 30 × 30

Distance = 900 m

Since the train started from a position of 1000 m , the final position will be:

Final position = 1000 + 900

Final position = 1900 metres

if you answer my question i will answer yours

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s