A proton starting from rest travels through a potential of 644 X 106V and then moves into a uniform magnetic field, B = 0.02 T, perpendicular to the protons velocity. What is the radius of the proton's resulting orbit in m? Mp 1.67 x 10-27 kg, e = 1.6 x 10-19 C.

Given :

Potential ,

Uniform magnetic field , B = 0.02 T .

Mass of proton , .

Charge on proton , .

Also , velocity of proton is perpendicular to magnetic field .

To Find :

The radius of the proton's resulting orbit .

Solution :

Now , when velocity is perpendicular to magnetic field radius of orbit is given by :

Putting all given values above :

Therefore , radius of orbit is 183.33 m .

Hence , this is the required solution .

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