The vertical component of a velocity vector points up and has a magnitude of 20, ms'. The velocity vector Itself makes an angle of 25' with the horizontal. Find the magnitude of the velocity vector.

Kindly check explanation

Explanation:

Given the following :

Vertical component has Magnitude = 20m/s

Angle made with the horizontal (θ) = 25°

Vy = Vsinθ = 20sin25

Vy = 20 × 0.4226182 = 8.4523652 m/s

Horizontal component :

Vx = Vcosθ = 20 × cos25

Vx = 20 × 0.9063077 = 18.126155 m/s

Hence, magnitude :

V = sqrt(Vx² + Vy²)

V = sqrt(8.4523652² + 18.126155²)

V = sqrt (399.99999)

V = 20m/s

answer: the exterior temperature of commercial jet planes as they leave the stratosphere and return to the ground increases steadily.

explanation:

the lower most layer of atmosphere is troposphere which extends from 0 to 12 km above the surface of the earth. the temperature initially decreases as distance is increased from the earth's surface. commercial jets fly in lower part of the stratosphere. the stratosphere extends upto 50 km. the temperature in stratosphere starts rising again due to presence of ozone which traps the uv rays.

thus, when the planes leave the stratosphere and return to the ground, the exterior temperature increases steadily.