A particle moves in a straight line with an initial velocity of 37 m/s and a constant acceleration of 20 m/s2. If at t = 0, x = 0, what is the particle's position (in m) at t = 6 s?

582 m

Explanation:

Given:

v₀ = 37 m/s

a = 20 m/s²

t = 6 s

Find: Δx

Δx = v₀ t + ½ at²

Δx = (37 m/s) (6 s) + ½ (20 m/s²) (6 s)²

Δx = 582 m

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