In the circuit given below all the resistors R1, R2, R3, R4 have the resistance of 1Ω connected to a battery of 5V. Determine the equivalent resistance and the current flowing in the circuit.

Answer for current is 6.667 A and resistance is 0.75 ohm

Explanation:

R1 R2 and R3 are in series because you can see its bent and joint.

So that whole branch is 3 ohm.

3 ohm parallel to 1 ohm is 0.75 ohm

Then by Ohm's Law

I= V/R= 5/0.75

= 6.667 A

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