An initially motionless test car is accelerated uniformly to 120 km/h in 8.28 s before striking a simulated deer. The car is in contact with the faux fawn for 0.815 s, after which the car is measured to be traveling at 71.0 km/h. What is the magnitude of the acceleration of the car before the collision

The value is  

Explanation:

From the question we are told that  

  The velocity  is  " alt="\frac{120 * 1000}{3600} = 33.3 \ m/s" />" />

  The time taken is

    The  time taken for contact is  

     The  velocity of the of the car after contact is " alt="\frac{71 *1000}{3600} = 19.7 2 \ m/s" />" />

From the equation of kinematics we have that  

Here   u =  0 \ m/s  since the car is initially motionless

=>    

=>    

multiply 2kg by latent heat of vap

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.