Physics, 12.10.2019 15:30 PinkDivaGirl02
Two cars collide at an icy intersection and stick together afterward. the first car has a mass of 1150 kg and was approaching at 5.00 m/s due south. the second car has a mass of 750 kg and was approaching at 25.0 m/s due west.
calculate the final velocity of the cars. (note that since both cars have an initial velocity, you cannot use equations 7.6a and b. you must look for other simplifying aspects.)
magnitude (answer in m/s
direction ° (counterclockwise from west is positive)
(b) how much kinetic energy is lost in the collision? (this energy goes into deformation of the cars.)
Answers: 2
= 1150 kg
=750 kg
= 5.00 m/s in y axis
= 25.0 m/s in x axis
![\Delta E = [\frac{1}{2}m_{1}u_{1}^2 +\frac{1}{2}m_{2}u_{2}^2 ] - \frac{1}{2}(m_{1}+m_{2})v^2\\\Delta E = [\frac{1}{2}\times1150\times5}^2 +\frac{1}{2}\times750 \times 25^2 ] - \frac{1}{2}(1150+750})10.3^2\\\Delta E = 147,964.5 J](/tpl/images/0313/4415/10665.png)
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