A pendulum is 0.760 m long, and the bob has a mass of 1,00 kg. At the bottom of its swing, the bob's speed is 1.60 m/s. The tension is greater than the weight of the bob because Multiple Choice 0 its horizontal component is increasing from zero. O the bob has a downward acceleration, so the net Fy must be downward O O the bob has zero acceleration. O ( the bob has an upward acceleration, so the net Fy must be upward Required information A pendulum is 0.760 m long, and the bob has a mass of 1.00 kg. At the bottom of its swing, the bob's speed is 1.60 m/s. What is the tension in the string at the bottom of the swing?

  T = 13.17 N

the correct one is there is a digested centripetal acceleration towards upward

Explanation:

For this exercise we can use Newton's second law at the bottom of the pendulum's path

we will assume that the upward direction is positive

              T - W = m a

in this case it is describing a circle the acceleration is central

              a = v² / R

where the radius of the trajectories equals the length of the pendulum

             R = L

we substitute

            T = mg + m v² / L

             T = m (g + v² / L)

When reviewing the different statements, the correct one is there is a digested centripetal acceleration towards upward

let's calculate the tension of the rope

             T = 1 (9.8 + 1.6 2 / 0.760)

             T = 13.17 N

trig 15.3 cos

f=ma newton's second law 7x8=56n