What is the magnitude of the thrust force before the cart is released?Express your answer in newtons using three significant figures.

Hello your question is incomplete below are missing parts

In this video, a small cart that has a mass of 600 grams rests on a table top. There is a fan on top of the cart, blowing air backwards at a steady rate. A stretched spring is attached to the back of the cart by a string, holding it in place. A scale, marked off in newtons, is positioned next to the spring and a small dot at the end of the spring indicates the magnitude of the spring force. The spring and scale together is called a “dynamometer.” Before the cart is released from the spring, the dynamometer reads approximately 1.9 newtons. The video is recorded at 60 frames per second, resulting in playback motion 2 times slower than normal. A frame counter indicates the current frame. A horizontal distance scale, marked off in centimeters, is also shown on the video. While the cart is at rest, the front edge of the front wheel is at the zero of the scale.

At frame 245, the string that attaches the cart to the spring is cut, releasing the cart, and it begins to roll forward. Using the distance scale, the position of the front edge of the front wheel can be tracked with

time. The following table indicates the position at different frames.

Frame            Position (cm)

245                  0.0

251                   1.9

257                  6.0

263                  13.9

269                  24.6

275                 38.4

281                  55.1

287                 75.0

Answer : 1.9 N

Explanation:

The magnitude of the thrust force before the cart is released can be calculated as :

60 fbs = 1 frame = 1/60 secs

therefore 6 frames = 1 / 10 secs

F fam = F spring = 1.9 N

Note: F thrust = F fam = 1.9 N

answer: its c lololo

answer: a. same unit

explanation: