A truck covers 40.0 m in 7.10 s while uniformly slowing down to a final velocity of 2.05 m/s. (a) Find the truck's original speed. m/s
(b) Find its acceleration. m/s^2

(A) Original speed= 9.22 m/s

(B) Acceleration= -1.0099 m\s^2

Explanation:

A truck covers 40m in 7.10 secs

The truck slows down at a uniform velocity of 2.05 m/s

(A) The original speed can be calculated as follows

Vo= 2(40)/7.10 - 2.05

= 80/7.10 - 2.05

= 11.2676 - 2.05

= 9.22m/s

(B) The acceleration can be calculated as follows

a= Vf-Vo/t

= 2.05-9.22/7.10

= -7.17/7.10

= -1.0099m/s^2

i wanna say it’s between b and d, leaning more towards b.

electrical power