A Van de Graaff generator is charged so that a proton at its surface accelerates radially outward at 1.35 ✕ 1012 m/s2. Find the following. (a) the magnitude of the electric force on the proton at that instant magnitude N direction ---Select--- (b) the magnitude and direction of the electric field at the surface of the generator magnitude N/C direction ---Select---

(a).

We know that force is

F = m a

So

F = (1.67 x 10^(-27) x (1.38 x10^12)

F = 2.3 x 10^-15 N facing the radially outward direction

(b).

Similarly Force for charge is

F = q E = m a

So relating

E = F/q = 2.3x 10^-15 /(1.6 10^ -19

E = 144.75 N/C facing the radially outward direction

in physics zero. in muscle fatigue could be high

find the sum of the two horizontal vectors and the sum of the two vertical vectors

isoceles right angled triangle