Suppose in a situation like Case A in the experiment, m1 = 200 g were at the 20-cm position and m2 = 100 g at the 65-cm position. Would there be a problem in experimentally balancing the system with m3 = 50 g? Explain. If so, how might the problem be resolved? In case 2(a):
m1 = 100 g
m2 = 200 g
m3 = 50 g

i guess that visual aids present persuasive examples to what you are presenting, some factors would be theme (does it fit with the color, information, what you are presenting), size (can you see it, is it a big enough span of data/information), and overall look of the visual aid.

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because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14

answer; equivalent to a one(1) horsepower motor;

that would be because of both gravity and friction. so     c