Two billiard balls, each with a mass of 0.17 kg, collide with each other on a pool table. Before the collision, one ball is moving south at 2.8 m/s and the
other ball is moving north at 1.6 m/s. What is the momentum of this system
after the collision?
A. 0.20 kg. m/s north
B. 0.20 kg m/s south
C. 0.60 kg m/s south
D. 0.60 kg: m/s north

Ibelieve the answer you're looking for is

Since you have not included the experiment situation and the data, of course, i can not give you specific details about it. but i can you with this question.1) i will assume that the motion is projectile (parabolic) motion.2) yes, the horizontal distance depends on the horizontal velocity as, naming vx the horizontal velocity and t the time, it is: x = vx × t3) now, observe that the flight time depends on the vertical velocity as, naming voy the initial vertical velocity, t the time and y the vertical distance before reaching the ground: y = yo + voy×t - gt² / 2.the higher the initial vertical velocity (voy) the longer the object will be flying and so t will be higher in the equation for the horizontal distance.that explains the relationship between the horizontal distance and the horizontal velocity.

  the answer is don't know.