1. Cassidy Reese is showing off her skydiving skills and testing the difference between shallow and deep braking configurations of her parachute. After a period of free fall, she deploys her chute and sets her parachute to shallow braking conditions where she has a velocity of vs = 12.0i hat − 4.5j m/s. After a period of time, Δts, she changes the setting to deep braking conditions, vd = 6.0i hat − 1.5j m/s, for the remainder of her dive. The simulation displays her trajectory for various Δts displaying the displacement in the x- and y-directions for both parts of her journey. Here, xs and ys are the x- and y-components of her displacement while the parachute is configured in the shallow braking conditions, and xdand yd are the components of her displacement while in the deep braking configuration.2. Cassidy decides to use her vast knowledge of physics to calculate what Δts to use if she wants to travel half the height (y-direction distance) in shallow braking and half the height in deep braking conditions. She uses the information about the velocities in the y-direction and the total y-displacement of 2400 m to calculate what Δts to use in order for the y-displacement to be the same in each part of her motion.1. Y velocity for shallow breaking 4.5m/s2. Y velocity in deep breaking 1.5m/sA. Total X-displacement from part 1 = 7800mB. Total displacement from part 1: 3840C. Total time part 1: 1000s (300s shallow) (700s deep)