PLEASE HELP MEEE THIS IS DUE TODAY AND MY GRADES ARE AT STAKE!:( A boy is used to riding his bike to school 5 miles north of his house. Yesterday he
decided to ride his bike from school to his friend's house which is located 1 mile
north of his house and it took him 0.2 hours to get there. Assuming the house is
the point of origin and north is a positive direction, what is the boy's velocity in
mph after reaching his friend's house? (Number response only and include a + or
- in front of the number with no space) *

They will be 140 miles apart 8 hours after the first boy started the trip or 6 hours after the second boy started the trip.

Explanation:

x = the time that the first boy travels at 14 mph

x - 2 = the time the second boy travels at 14 mph

140 the distance between them

Since one travels north and the other east (their roads are perpendicular) the distance between them can be calculated using Pythagorean Theorem

(14*x)^2 + ((x-2)*14)^2 = 140^2

the solutions of the quadratic equation are

x1 = - 6 is not the solution since x > 0

x2 = 8 h is the solution

+5mph North

Explanation:

He rode one mile North, in 0.2 hours. There are 60 minutes in an hour.

60 x 0.2 = 12

It took him 12 minutes to get to his friends house.

60 / 12 = 5

Assuming he were to keep up a steady pace and go an entire mile, he would have ridden 5 miles in the span of that mile.

the maxium height is 34m/s