while walking to school you approach an intersection and slow down from 2m/s to a stop 3s .what was your acceleration during this time interval?

0.667 m/s^2

Explanation: Given that you slow down from 2m/s to a stop 3s.

Using first law of motion.

V = U - at

Where

Final velocity V = 0

Initial velocity U = 2 m/s

Time taken t = 3 seconds

Since the body slow down, the final velocity V will be equal to zero. And the acceleration will be negative.

Substitute all the parameters into the formula

0 = 2 - a × 3

3a = 2

a = 2 /3

a = 0.667 m/s^2

Therefore, your acceleration during this time interval will be 0.667 m/s^2

v=ir = 3x15 =45 v