PLEASE HELP !! KINEMETICS A car is traveling at -18 m/s when the driver sees a disabled car in the middle of the road. She takes 0.8 s to react (assume that the car travels at constant speed during this reaction time). She then steps on the brakes and slows at a rate of 9.0 m/s2. How much time does the car need to stop? How far does the car go before it stops? This is a multi step problem.

Please show work !!

Explanation:

Given that,

The initial speed of the car, u = -18 m/s

Reaction time, t = 0.8 s

The acceleration of the car is 9 m/s²

We need to find the time taken by the car to stop. Using first equation of motion to find it as follows :

v = u +at

Put v = 0

Let d is the distance covered by the car before it stops. Using third equation of kinematics as follows :

Hence, it will take 2 seconds to stop the car and the distance covered is 18 m.