A V-shaped distribution of charge of width 2L and linear charge density lambda is positioned as shown in the fi gure. The V-shape
is formed by the lines y = x and y = -x between x = -L and
x = L as shown.

What direction will the electric field be and why?

Set up, but do not evaluate, the integral giving the electric field at the point y0. Assume y0 > L (but
not y0 -L). Your answer should contain only the variables k, lambda, y0, the integral and integration variable, and
possibly a numerical constant.

wavelegth as in spectrum red oygbiv

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

where is unknown. because the position is parabolic, there is symmetry about the midpoint at , and we know that

so that the position function is

which means the velocity is

then the total distance traveled is

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at and ends at , so its displacement is 0.