-8.0 36-450655) =(4579
4) An 65-kg baseball player slides into second base. The coefficient of kinetic
friction between the player and the ground is 0.49. (a) What is the magnitude
of the frictional force? (b) If the player comes to rest after 16 s, what was his
initial velocity?

No it doesnt because it can be any number.

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j