11. A bicycle with an initial velocity of +6 m/s accelerates at a rate of +2 m/s2 for 3 seconds. What distance does the bicycle travel during this time?
C С
18 m
9 m
27 m
36 m

Explanation:

Given:

Initial Velocity = = 6 m/s

Acceleration = a = 2 m/s²

Time = t = 3 secs

Required:

Distance = S = ?

Formula:

Solution:

S = (6)(3) + 1/2 (2)(3)²

S = 18 + 9

S = 27 m

Hope this helped!

3.2x10^7

if they have a finite resultant