A blue shark accelerates at a rate of 16m/s for a time of 0.8s. During this time it travels a distance of 11.52m. Calculate its initial speed.

The initial velocity of this shark is . (Assuming that the unit of the acceleration in this question is .)

Explanation:

Let denote the acceleration of this shark.

Let denote the initial velocity of this shark.

Assume that the acceleration of this shark is constant (as it is in this question.) Over a period of time , the shark would have travelled a distance of:

.

This question states that:

This question is asking for , the initial velocity of this shark at the beginning of this -second period. Substitute the three known values into the equation:

.

Solve for :

.

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz