The resistances of two bulbs are in ratio 2:3 .The bulbs are connected in series across a battery. Find the ratio of powers in the bulbs.

Ratio of resistances of two bulbs = 2:3

Both are connected in series.

We have to find the ratio of powers in the bulbs..

We know that, current flow through each conductor in series connection remains same. So, we have to use that formula of power which shows relation between current and resistance.

For series connection; P ∝ R

→ P₁/P₂ = R₁/R₂

→ P₁/P₂ = 2/3

→ P₁ : P₂ = 2 : 3

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees.