you are at the grand canyon standing at the edge of a ledge 1857 m high you have a mass of 61 kg. you decide to take a selfie to share with your science teacher when you get home which causes you to wonder how much gravitational potential energy do you have standing at the edge of this cliff

1,110,114.6 J

Explanation:

The height is 1857m, the mass is 61 kg, and the accelaration is 9.8 m/s^2. Plug in the equation GPE=h*m*a and you get 1,110,114.6.

h= height

m= mass

a= accelaration

GPE= gravitational potential energy

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz

the closer the planet is to the sun, the larger the gravity