A car starts from rest and accelerates uniformly over a time of 5.21 seconds for a distance of 110 m. Determine the acceleration of the car.

8.1m/s^2

Explanation:

For this question, in order to solve it, we have to use the second equation of motion which will be:

s = ut + 1/2at^2

where,

u = initial velocity

v = final velocity

t = time

a = acceleration

Since u = 0, then

a = 2s/t^2

a = 2 × 110/5.21^2

a = 220/27.1441

a = 8.1m/s^2

the answer is a. at the equator

yup its correct its: c) b b