Afeather is dropped onto the surface of the moon. how far will the feather have fallen if it reaches the surface in 9.00 seconds?
given: g on moon = -1.63 meters/second2

   Distance of fall = (1/2) · (acceleration of gravity) · (time)²

                         =  (1/2)    ·      (1.63 m/s²)   ·   (9 sec)²

                         =          (0.815 m/s²)          ·    (81 sec²)

                         =                    66 meters  .

On Earth ... IF there were no air ... the feather would fall
397 meters in the same amount of time !

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.