a 3000 kg car accelerates uniformly from 15 m/s to 60 m/s in 5 seconds. determine the net force on the car during this time

F = 2700 N

Explanation:

Given that,

Mass of a car, m = 3000 kg

Initial velocity, u = 15 m/s

Final velocity, v = 60 m/s

Time, t = 5 s

We need to find the net force on the car during this time . The net force on an object is given by the product of mass and acceleration. So,

F = ma

a is acceleration, a = (v-u)/t

So, 27000 N is the net force on the car during this time .

given data:

determine the horse power (h.p) = ?

force applied to move the box(f) = 10 pounds,

box lifted from a distance         (d) = 3 feet

time taken to lift                         (t) = 10 sec,

the horse power is defined as amount of work required to move a load. the horse power is equal to 550 foot-pound per second

                  1 h.p   = 550 foot-pound/second

it can also be defined as the the load that need to be move a body for certain distance in a certain amount of time.

mathematically,

                      h.p = (force × distance)/ time

                            = (10 × 3)/ 10

                            = 30/10

                            = 3 foot -pound/sec

hence, the horse power is needed to move the box is 3 foot-pound/second

important note: 1 h.p = 550 foot-pound/second = 746 watts

the old price per ounce is c/4.

the new price per ounce is c/3.6.

the ratio of the old price to the new one is

(c/4)/(c/3.6) = (c/c)×(3.6/4) = 0.9 . . = 9/10 . . "nine tenths" in either form