a car on a circular track accelerates from rest. the radius of the track is 0.30km and the magnitude of the constant angular acceleration is 4.5x10-3 rads/s squared. find the centripetal acceleration of the car when it has completed half of a lap.

The centripetal acceleration of the car is 50.4 m/s²

Explanation:

Given;

radius of the track, r = 0.3km = 300 m

constant angular acceleration, α = 4.5 x 10⁻³ rad/s²

during half of a lap, θ = π

Determine time of motion

θ = ωt + ¹/₂αt²

π = 0 + ¹/₂αt²

t² = 2π / α

t² = ( 2 x 3.142) / (4.5 x 10⁻³)

t² = 1396.44

t = √1396.44

t = 37.369 s

Determine the angular velocity

Determine the centripetal acceleration of the car

Therefore, the centripetal acceleration of the car is 50.4 m/s²

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