Suppose that a car starts from rest at t = 0. The car moves with an acceleration of 1.5 m/s2. How far will the car travel in 3.0 s?

To find the distance traveled by the car in 3 seconds is equal to 6.75 meters.

Given the following data:

To find the distance traveled by the car in 3 seconds, we would apply the second equation of motion:

Mathematically, the second equation of motion is given by the formula;

Where:

Substituting the given parameters into the formula, we have;

Distance, S = 6.75 meters.

Read more on acceleration here: link

6.75m

Explanation:

To calculate the distance in this question, we can use the formula:

S = ut + 1/2at^2

Where; S = distance

u = initial velocity = 0m/s

t = 3s

a = 1.5m/s^2

Hence:

S = (0 × 3) + 1/2 (1.5 × 3 × 3)

S = 0 + 1/2 (13.5)

S = 13.5/2

S = 6.75

Therefore, the car will travel 6.75m in 3seconds.

the total distance that martina travels that day is

(distance from home to mom's office) plus (distance from mom's office to school)

plus (distance from school to library) plus (distance from library to friend's house)

plus (distance from friend's house to martina's house).

(we don't know what any of these distance actually is.)