Physics, 18.10.2020 15:01 marianasanin2007

What is the elapsed time between the 0-m mark and the 40-m mark

Answers: 1

Show answers

Answers

Answer from: estrellagutierrez12

a) 4.0 s

b) 16 m/s

c) The distance covered between 4 - 5 s is four times the distance covered between 4 - 5 s

d) Equal distance are covered between 0 - 4 s and 4 -5 s

Note: The question is incomplete. The complete question is as follows;

Refer to the chart below that has data about a moving object to answer the following questions.

Time Elapsed 0.0s 1.0s 2.0s 3.0s 4.0s 5.0 s

Distance Traveled 0.0m 10.0m 20.0m 30.0m 40.0m 80.0 m

a. What is the elapsed time between the 0-m mark and the 40-m mark?

b. How large is the average velocity of the object for the interval from 0-5 s ?

c. How does the interval of 3-4 s compare with the interval from 4-5 s in terms of distance?

d. How does the interval of 0-4 s compare with the interval from 4-5 s in terms of distance?

Explanation:

a. From the data provide, time elapsed between the 0 m - 40 m mark is 4.0 s

b. Average velocity = total distance/ total time

average velocity = 80 m/ 5.0 s = 16.0 m/s

c. Distance covered between 3 - 4 s = 40 m - 30 m = 10 m

Distance covered between 4 - 5 s = 80 m - 40 m = 40 m

The distance covered between 4 - 5 s is four times the distance covered between 4 - 5 s

d. Distance covered between 0 - 4 s = 40 m - 0 m = 40 m

Distance covered between 4 - 5 s = 80 m - 40 m = 40 m

Equal distance are covered between 0 - 4 s and 4 -5 s

Answer from: Quest

beta is electron from nucleus

something from nucleus has changed, but charge must be same for cons of charge

Answer from: Quest

Answerthe force between the charges will be f/9 (one-ninth of force f)explanationcoulomb's law relates the magnitudes two point charges q₁ and q₂, the distance, r, between the charges, and the electrostatic force, f, between the two charges: $f = \dfrac{k q_1 q_2}{r^2}$ k represents coulomb's constant, k = 8.99×10⁹ n·m²/c².note that if we have r = 3r, then $\begin{aligned} f & = \dfrac{k q_1 q_2}{r^2} \\ f_{3r} & = \dfrac{k q_1 q_2}{(3r)^2} \\ & = \dfrac{k q_1 q_2}{3^2 \cdot r^2} \\ & = \frac{1}{9} \cdot \boxed{\dfrac{k q_1 q_2}{r^2} } \\ & = \frac{1}{9} f & & \left(\text{\footnotesize since $ f = \tfrac{k q_1 q_2}{r^2}$}\right) \end{aligned}$

Another question on Physics

Physics, 22.06.2019 06:00

When you push downward on a book at rest on a table, you feel an upward force. does this force depend on friction? defend your answer.

Answers: 2

Answer

Physics, 22.06.2019 14:00

How to tell if two objects are in thermal equilibrium 1.the objects have the same temperature 2.the objects are the same size 3.the objects are touching each other 4.the objects temperatures are changing

Answers: 1

Answer

Physics, 22.06.2019 17:00

Air conditioners not only cool air, but dry it as well. suppose that a room in a home measures 5.0m×9.0m×2.4m . if the outdoor temperature is 30 ∘c and the vapor pressure of water in the air is 85 % of the vapor pressure of water at this temperature, what mass of water must be removed from the air each time the volume of air in the room is cycled through the air conditioner? the vapor pressure for water at 30 ∘c is 31.8 torr.

Answers: 3

Answer

Physics, 22.06.2019 19:00

The law of reflection states that the angle of reflection is equal to the angle of

Answers: 1

Answer

You know the right answer?

What is the elapsed time between the 0-m mark and the 40-m mark...

Questions