This diagram shows two different forces acting on a skateboarder. The combined mass of the skateboard and the person is 81.5 kg. Based on this information, what is the acceleration of the skateboarder? A. 0.51 m/s² to the left
B. 1.95 m/s² to the left
C. 0.51 m/s² to the right
D 1.94 m/s² to the right

Option C. 0.51 m/s² to the right.

Explanation:

We'll begin by calculating the net force acting on the skateboarder. This is illustrated below:

Force applied (Fₐ) = 52.8 N

Force resistance (Fᵣ) = 11.4 N

Net force (Fₙ) =.?

Net force (Fₙ) = Force applied (Fₐ) – Force resistance (Fᵣ)

Fₙ = Fₐ – Fᵣ

Fₙ = 52.8 – 11.4

Fₙ = 41.4 N to the right

Thus, the net force acting on the skateboarder is 41.4 N to the right.

Finally, we shall determine the acceleration of the skateboarder as shown below:

Mass (m) = 81.5 kg.

Net force (Fₙ) = 41.4 N to the right

Acceleration (a) =..?

Net force (Fₙ) = mass (m) × acceleration (a)

Fₙ = ma

41.4 = 81.5 × a

Divide both side by 81.5

a = 41.4 / 81.5

a = 0.51 m/s² to the right.

Therefore, the acceleration of the skateboarder is 0.51 m/s² to the right.

amplitude

hope this

k2s for potassium sulphide