Answers: 2
above the height of the fire hose, assuming that air resistance is negligible and that 
.
(towards the ground.)Horizontally, water particles would travel at a constant velocity.
. Angle of elevation: 
. Calculate the initial velocity of these water particles in these two components:
.Initial vertical velocity: 
.
at a constant horizontal speed of 
. Therefore:
.
into its flight when it hits the building. What would be its height? Assuming that the air resistance on that particle is negligible. The height of that water particle at time 
may be modeled using the SUVAT equation:![\displaystyle x(\text{vertical}) = \frac{1}{2}\, a \, t^{2} + \left[v_0(\text{vertical})\right]\, t](/tpl/images/0823/9740/110d8.png)
,
gives the height of the water particle (relative to where it was launched.)
(negative because gravitational acceleration points towards the ground.)
(see above.)
(that's the time when the water particle hits the building.)![\begin{aligned}x(\text{vertical}) &= \frac{1}{2}\, a \, t^{2} + \left[v_0(\text{vertical})\right]\, t \\ &\approx \frac{1}{2} \times \left(-9.81\; \rm m \cdot s^{-2}\right) \times (3.6\; \rm s)^2 + 21.7\; \rm m \cdot s^{-1} \times 3.6\; \rm s \\ &\approx 14\; \rm m\end{aligned}](/tpl/images/0823/9740/cf089.png)
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The water from a fire hose is directed at a building . The water leaves the pipe at a speed of 25 m/...
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