A student connects four AA batteries (1.5 V each) in series to light up a light bulb. The circuit has a resistance of 50 Ω. How much current flows through the circuit?

0.3

Explanation:

V = I R

1.5= I (50)

I = 1.5/50

I = 0.3 J

Therefore, 0.3joule current flows through the circuit.

Hope this helped

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases . this process does not change the mass number.

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as -decay. in this the mass number remains same.

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

wire in brush may conduct electricity from cell to drill and vice versa electrc shock possible