A frog is sitting on a lily pad when it sees a delicious fly. He darts out his tongue at a speed of 3.90 m/s to catch the fly. The tongue has a mass of 0.410 g, and the rest of the frog plus the lily pad have a mass of 12.5 g. What is the recoil speed of the frog and the lily pad? Ignore drag forces on the pad due to the water.

Recoil speed of the frog and the lily pad, v₂  = 0.124 m/s

Explanation:

According to the law of conservation of linear momentum, in a closed system of colliding bodies, the momentum before collision is equal to the momentum after collision.

Momentum before collision = m₁v₁

momentum after collision = (m₁ + m₂)v₂

where m₁ = mass of the tongue; v₁ = velocity of the tongue; m₂ = mass of th frog and lily pad; v₂ = velocity of the frog and lily pad

m₁v₁ = (m₁ + m₂)v₂

v₂ = (m₁v₁)/(m₁ + m₂)

m₁ = 0.41 0 g = 0.00041 kg; v₁ = 3.90 m/s/; m₂ = 12.5 g = 0.0125 kg; v₂  = ?

v₂ = (0.00041 kg * 3.90 m/s)/(0.000410 + 0.0125 kg)

v₂ = 0.124 m/s

that would be because of both gravity and friction. so     c

i think its c if i'm wrong